Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 10

Answer

$9\sqrt{3}$

Work Step by Step

Simplify each radical, when needed, to have: $=4\sqrt{3}-5\sqrt{4(3)} + 3\sqrt{25(3)} \\=4\sqrt{3} - 5\cdot 2\sqrt{3} + 3\cdot 5\sqrt{3} \\=4\sqrt{3} - 10\sqrt{3} + 15\sqrt{3}$ Combine like terms to have: $=(4-10+15)\sqrt{3} \\=9\sqrt{3}$
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