Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-28: 8

Answer

$8$

Work Step by Step

$\sqrt{2} \cdot \sqrt{32} \\=\sqrt{2(32)} \\=\sqrt{64} \\=8$
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