Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises: 48

Answer

$=\dfrac {3}{111}$

Work Step by Step

$0.\overline {027}=0.027027...=\dfrac {27}{1000}+\dfrac {27}{1000^{2}}+...=\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {27}{1000}}{1-\dfrac {1}{000}}=\dfrac {27}{999}=\dfrac {3}{111}$
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