Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises: 46

Answer

$=\dfrac {3}{11}$

Work Step by Step

$0.\overline {27}=0.272727...=\dfrac {27}{100}+\dfrac {27}{100^{2}}+\dfrac {27}{100^{3}}+\ldots =\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {27}{100}}{1-\dfrac {1}{100}}=\dfrac {\dfrac {27}{100}}{\dfrac {99}{100}}=\dfrac {27}{99}=\dfrac {3}{11}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.