Answer
$\Sigma_{k=4}^{12}2^k =8176$
Work Step by Step
$\Sigma_{k=4}^{12}2^k $
$a=2^4=16$
$r=2$
# of terms $= 12-4+1=9$
$$\Sigma_{k=4}^{12}2^k =\frac{16(1-(2)^9)}{1-2}=8176$$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises - Page 623: 10
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