Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 77

Answer

2

Work Step by Step

$\lim\limits_{x\to 1}$ $\frac{x-1}{\sqrt x-1}$ = $\lim\limits_{x\to 1}$ $\frac{(\sqrt x-1)(\sqrt x+1)}{\sqrt x-1}$ = $\lim\limits_{x\to 1}$ $\sqrt x+1$ = $\sqrt 1$+1 =2
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