Answer
$80$
Work Step by Step
$\lim _{x\rightarrow 2}\dfrac {x^{5}-32}{x-2}=\lim _{x\rightarrow 2}\dfrac {\left( x-2\right) \left( x^{4}+x^{3}\times 2+x^{2}2^{2}+x\times 2^{3}+2^{4}\right) }{\left( x-2\right) }=x^{4}+2x^{3}+4x^{2}+8x+16=16+16+16+16+16=80$
