Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 65

Answer

$10$

Work Step by Step

$\lim _{h\rightarrow 0}\dfrac {\left( 5+h\right) ^{2}-25}{h}=\dfrac {25+10h+h^{2}-25}{h}=\dfrac {10h+h^{2}}{h}=\dfrac {h\left( 10+h\right) }{h}=10+h=10+0=10$
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