Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 71

Answer

6

Work Step by Step

$\lim\limits_{x \to 1}$ $\frac{x^{6}-1}{x-1}$ = $\lim\limits_{x \to 1}$ $\frac{(x-1)(x^5+x^4+x^3+x^2+x+1)}{x-1}$ = $\lim\limits_{x \to 1}$ $x^5+x^4+x^3+x^2+x+1$ = 1+1+1+1+1+1 = 6
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