Answer
6
Work Step by Step
$\lim\limits_{x \to 1}$ $\frac{x^{6}-1}{x-1}$
= $\lim\limits_{x \to 1}$ $\frac{(x-1)(x^5+x^4+x^3+x^2+x+1)}{x-1}$
= $\lim\limits_{x \to 1}$ $x^5+x^4+x^3+x^2+x+1$
= 1+1+1+1+1+1
= 6
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 78: 71
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