Answer
$\int_{0}^{2} \int_{0}^{1} 4xy$ $dxdy = 4$
Work Step by Step
$\int_{0}^{2} \int_{0}^{1} 4xy$ $dxdy$
Integrate with respect to $x$:
$\int_{0}^{2} 2x^2y |_0^1$ $dy$ $=$ $\int_{0}^{2} [2(1^2)y - 2(0)^2y]$ $dy$ $=$ $\int_{0}^{2}2y$ $dy$
Integrate with respect to $y$:
$y^2|_{0}^{2} = 2^2-0^2=4$