Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.5 The Chain Rule - 2.5 Exercises: 37

Answer

$$y'=-2\cot(\sin\theta)\csc^2(\sin\theta)\cos\theta$$

Work Step by Step

$$y'=(\cot^2(\sin\theta))'=2\cot(\sin\theta)(\cot(\sin\theta))'= 2\cot(\sin\theta)(-\frac{1}{\sin^2(\sin\theta)})(\sin\theta)'=-2\cot(\sin\theta)\csc^2(\sin\theta)\cos\theta$$
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