Answer
$f'(θ)= -2θsin(θ^2)$
Work Step by Step
Original Expression: $f(θ) = cos(θ^2) $
$u=θ^2$
$f(u)= cos(u)$
Apply the chain rule: $f'(u)u'$
$f'(u)= -sin(u)2θ$
$f'(θ)= -2θsin(θ^2)$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 2 - Derivatives - 2.5 The Chain Rule - 2.5 Exercises - Page 158: 13
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