Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises - Page 140: 25

Answer

$f'(x)=25x^4+39x^2-6$

Work Step by Step

$f(x)=(5x^2-2)(x^3+3x)$ Use the product rule. $f'(x)=(5x^2-2)(3x^2+3)+(x^3+3x)(10x)$ Distribute. $f'(x)=15x^4+15x^2-6x^2-6+10x^4+30x^2$ Combine like terms. $f'(x)=25x^4+39x^2-6$
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