Answer
$g'(t) = -\frac{3}{2}t^{-\frac{7}{4}}$
Work Step by Step
$g(t) = 2t^{-\frac{3}{4}}$
Power Rule
$g'(t) = 2(-\frac{3}{4})t^{-\frac{3}{4}-1}$
Simplify
$g'(t) = -\frac{3}{2}t^{-\frac{7}{4}}$
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