Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises: 20

Answer

$G'(t)=\dfrac{\sqrt{5}}{2\sqrt{t}}-\dfrac{\sqrt{7}}{t^{2}}$

Work Step by Step

Rewrite the function $G(t)=\sqrt{5}t^{1/2}+\sqrt{7}t^{-1}$ Derivate apply power rule $G'(t)=\dfrac{\sqrt{5}}{2}t^{-1/2}-\sqrt{7}t^{-2}$ $G'(t)=\dfrac{\sqrt{5}}{2\sqrt{t}}-\dfrac{\sqrt{7}}{t^{2}}$
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