Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises - Page 140: 13

Answer

$S(p)=\frac{1}{2\sqrt p}-1$

Work Step by Step

$S(p)=\sqrt p-p$ Use the power rule. $S(p)=\frac{1}{2\sqrt p}-1$
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