Answer
$$\frac{dy}{dx}=\frac{33(x-5)^2}{(2x+1)^4}$$
Work Step by Step
$$\frac{dy}{dx}=\Big(\Big(\frac{x-5}{2x+1}\Big)^3\Big)'=3\Big(\frac{x-5}{2x+1}\Big)^2\Big(\frac{x-5}{2x+1}\Big)'=
3\Big(\frac{x-5}{2x+1}\Big)^2\frac{(x-5)'(2x+1)-(x-5)(2x+1)'}{(2x+1)^2}=
3\Big(\frac{x-5}{2x+1}\Big)^2\frac{2x+1-2x+10}{(2x+1)^2}=
3\Big(\frac{x-5}{2x+1}\Big)^2\frac{11}{(2x+1)^2}=\frac{33(x-5)^2}{(2x+1)^4}$$
