Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6: 21

Answer

$f'(x)=28x^6\sec^2(x^7)\tan(x^7)$

Work Step by Step

$f(x)=2sec^2(x^7)$ $f'(x)=4sec^1(x^7)\times\frac{dy}{dx}(sec(x^7))$ $f'(x)=4sec(x^7)\times{sec(x^7)tan(x^7)}\times7x^6$ $f'(x)=28x^6\sec^2(x^7)\tan(x^7)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.