Answer
$f'(x)=-20\sin x\cos^{4}x$
Work Step by Step
$f(x)=4cos^5x$
$f'(x)=4\times{5cos^{5-1}x}\times(\frac{d}{dx})(cosx)$
$f'(x)=20cos^{4}x\times(-sinx)$
$f'(x)=-20\sin x\cos^{4}x$
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