Answer
$$\frac{dy}{dx}=3\cos(\tan3x)\sec^23x$$
Work Step by Step
$$\frac{dy}{dx}=(\sin(\tan 3x))'=\cos(\tan3x)\cdot(\tan3x)'=\cos(\tan3x)\sec^23x\cdot(3x)'=\cos(\tan3x)\sec^23x\cdot3=3\cos(\tan3x)\sec^23x$$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6 - Page 158: 32
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