Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6: 32

Answer

$$\frac{dy}{dx}=3\cos(\tan3x)\sec^23x$$

Work Step by Step

$$\frac{dy}{dx}=(\sin(\tan 3x))'=\cos(\tan3x)\cdot(\tan3x)'=\cos(\tan3x)\sec^23x\cdot(3x)'=\cos(\tan3x)\sec^23x\cdot3=3\cos(\tan3x)\sec^23x$$
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