Answer
$\frac{d^2y}{dx^2}=\csc^3x+\cot^2x\csc x$
Work Step by Step
$y=cscx$
$\frac{dy}{dx}=−cotxcscx$
$\frac{d^2y}{dx^2}=−(\frac{d}{dx}(cotx)\times{cscx}+cotx\times{\frac{d}{dx}(cscx)})$
$\frac{d^2y}{dx^2}=−(−csc^2x\times{cscx}+cotx\times{−cotxcscx)}$
$\frac{d^2y}{dx^2}=\csc^3x+\cot^2x\csc x$