Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5 - Page 151: 10

Answer

$f'(x)=-\sin x-\csc x+x\cot x\csc x$

Work Step by Step

$f(x)=cosx-xcscx$ $f'(x)=-sinx-(\frac{d}{dx}(x)\times{cscx}+x\times{\frac{d}{dx}(cscx)}$ $f'(x)=-sinx-(1\times{cscx}+x\times{-cotxcscx})$ $f'(x)=-sinx-(cscx-xcotxcscx)$ $f'(x)=-\sin x-\csc x+x\cot x\csc x$
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