Answer
$f'(x)=4x^{2}\sin x-8x\cos x$
Work Step by Step
$f(x)=-4x^{2}cos x$
$f'(x)=-4x^{2}\frac{d}{dx}[cosx]+cosx\frac{d}{dx}[-4x^{2}]$
$f'(x)=-4x^{2}(-\sin x)+\cos x(-4)(2)x$
$f'(x)=4x^{2}\sin x-8x\cos x$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5 - Page 151: 3
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
