Answer
$f'(x)=0$
Work Step by Step
$f(x)=sec^2x-tan^2x$
Recall that $(tan^2x+1\equiv sec^2$)
$f(x)=1$
$f'(x)=0$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5 - Page 151: 16
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