Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.6 Exercises - Page 138: 5

Answer

$\left[\begin{array}{l}110 \\ 120\end{array}\right]$

Work Step by Step

\[ \begin{array}{l} x=C x+d \\ =(I-C) x+d \\ x=(I-C)^{-1} d \end{array} \] Given production model. \[ I-C=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]-\left[\begin{array}{cc} 0 & .5 \\ .6 & .2 \end{array}\right]=\left[\begin{array}{cc} 1 & -.5 \\ -.6 & .8 \end{array}\right] \] Find the value of I-C. \[ (I-C)^{-1}=\left[\begin{array}{ll} 1.6 & 1 \\ 1.2 & 2 \end{array}\right] \] Inverse of I-C. \[ x=\left[\begin{array}{ll} 1.6 & 1 \\ 1.2 & 2 \end{array}\right]\left[\begin{array}{l} 50 \\ 30 \end{array}\right]=\left[\begin{array}{l} 110 \\ 120 \end{array}\right] \]
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