Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.2 Exercises - Page 111: 5

Answer

x=$\begin{bmatrix}7\\ -9\\\end{bmatrix}$

Work Step by Step

$A^{-1}$= $\begin{bmatrix} 2&-3\\ -\frac{5}{2}&4\\ \end{bmatrix}$ x= $A^{-1}$b $\begin{bmatrix} x_{1}\\ x_{2}\\\end{bmatrix}$= $\begin{bmatrix}2&-3\\ -\frac{5}{2}&4\\\end{bmatrix}$$\begin{bmatrix} 2\\ -1\\\end{bmatrix}$=$\begin{bmatrix}2(2)+(-3)(-1)\\ -\frac{5}{2}(2)+4(-1)\\\end{bmatrix}$= $\begin{bmatrix}7\\ -9\\\end{bmatrix}$
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