Answer
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
Answer: (1 1/$\frac{-7}{5}$ $\frac{-8}{5}$)
Work Step by Step
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
This is a 2x2 matrix, therefore let A = (a b/ c d) if ad-bc ≠ 0.
Thus, $A^{-1}$ = $\frac{1}{ad-bc}$ × (d -b/-c a)
ad-bc = 8×(-5) - (-7)×5. Thus, ad-bc = -5
$A^{-1}$ = $\frac{-1}{5}$ × (-5 -5/7 8) which is (1 1/$\frac{-7}{5}$ $\frac{-8}{5}$)
