Answer
$D=A^{-1}$
Work Step by Step
Let $A$ be invertible and $AD=I$
$AD=I$
$A^{-1}(AD)=A^{-1}I$
$(A^{-1}A)D=A^{-1}$
$ID=A^{-1}$
$D=A^{-1}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 2 - Matrix Algebra - 2.2 Exercises - Page 111: 8
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