Answer
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
Answer: (-2 1/$\frac{7}{2}$ $\frac{-3}{2}$)
Work Step by Step
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
This is a 2x2 matrix, therefore let A = (a b/ c d) if ad-bc ≠ 0.
Thus, $A^{-1}$ = $\frac{1}{ad-bc}$ × (d -b/-c a)
ad-bc = 3×4 - 7×2. Thus, ad-bc = -2
$A^{-1}$ = $\frac{-1}{2}$ × (4 -2/-7 3) which is (-2 1/$\frac{7}{2}$ $\frac{-3}{2}$)
