Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 49

Answer

$(x-1)^2$

Work Step by Step

RECALL: A perfect square trinomial can be factored using either of the following formulas: (i) $a^2+2ab+b^2= (a+b)^2$ (ii) $a^2-2ab+b^2=(a-b)^2$ The given perfect square trinomial can be written as: $=x^2- 2(x)(1) + 1^2$ This trinomial has the same form as the perfect square trinomial in formula (ii) above. Factor using formula (ii) with $a=x$ and $b=1$ to obtain: $=(x-1)^2$
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