Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 37

Answer

$3y(y-4)(y+4)$

Work Step by Step

Factor out $3y$ to obtain: $=3y(y^2-y16)$ Write 16 as $4^2$ to obtain: $=3y(y^2-4^2)$ The binomial is a difference of two squares. RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ Factor the difference of two squares using the formula above with $a=y$ and $b=4$ to obtain: $=3y(y-4)(y+4)$
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