Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.4 - Factoring Special Forms - Exercise Set: 41

Answer

$-3(x-5)(x+5)$

Work Step by Step

Factor out $-3$ to obtain: $=-3(x^2-25)$ Write $25$ as $5^2$ to obtain: $=-3(x^2-5^2)$ The binomial is a difference of two squares. RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ Factor the difference of two squares using the formula above with $a=x$ and $b=5$ to obtain: $=-3(x-5)(x+5)$
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