Answer
$(xy-3)(x^2y^2+3xy+9)$
Work Step by Step
The given binomial can be written as:
$(xy)^3-3^3$
The binomial above is a difference of two cubes.
RECALL:
A difference of two cubes can be factored using the formula:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Use the formula above to factor the difference of two cubes with $a=xy$ and $b=3$ to obtain:
$=(xy-3)[(xy)^2+xy(3) + 3^2]
\\=(xy-3)(x^2y^2+3xy+9)$
