Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set: 25

Answer

V=48$\pi$ m$^3$$\approx$151 m$^3$

Work Step by Step

V=$\frac{1}{3}$h$\pi$r$^2$ V=$\frac{1}{3}$(9)$\pi$(4)$^2$ V=3$\pi$(4)$^2$ V=3$\pi$(16) V=48$\pi$ m$^3$$\approx$151 m$^3$
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