Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set: 24

Answer

V=2304$\pi$ in$^3$$\approx$7238 in$^3$

Work Step by Step

r=$\frac{1}{2}$d r=$\frac{1}{2}$(24) r=12 V=$\frac{4}{3}$$\pi$r$^3$ V=$\frac{4}{3}$$\pi$(12)$^3$ V=$\frac{4}{3}$$\pi$(1728) V=$\frac{1728(4)}{3}$$\pi$ V=$\frac{6912}{3}$$\pi$ V=2304$\pi$ in$^3$$\approx$7238 in$^3$
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