Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set - Page 178: 26

Answer

V=$\frac{400}{3}$$\pi$ m$^3$$\approx$419 m$^3$

Work Step by Step

V=$\frac{1}{3}$$\pi$r$^2$h V=$\frac{1}{3}$$\pi$(5)$^2$(16) V=$\frac{1}{3}$$\pi$(25)(16) V=$\frac{1}{3}$$\pi$(400) V=$\frac{400}{3}$$\pi$ m$^3$$\approx$419 m$^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.