Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set: 32

Answer

28$^\circ$, 84$^\circ$, and 68$^\circ$

Work Step by Step

Since one angle is 3 times the measure of the other, these angles can be represented by x and 3x. The third angle is 40$^\circ$ greater than the smaller one, so it can represented by x+40. The sum of all of the angles in a triangle is always 180$^\circ$. x+3x+x+40=180 4x+x+40=180 5x+40=180 5x=180-40 5x=140 x=$\frac{140}{5}$ x=28$^\circ$ 3x=3(28)=84$^\circ$ x+40=(28)+40=68$^\circ$
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