Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 95

Answer

$-\dfrac{8}{y^7}$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}, a\ne0$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Divide the numerical coefficients then use rule (i) above to obtain: $=-8y^{3-10} \\=-8y^{-7}$ Use rule (ii) above to obtain: $=-8 \cdot \dfrac{1}{y^7} \\=-\dfrac{8}{y^7}$
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