Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 93

Answer

$\dfrac{1}{x^{18}}$

Work Step by Step

RECALL: (i) $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$ (ii) $(a^m)^n=a^{mn}$ Use rule (ii) above to obtain: $=x^{3(-6)} \\=x^{-18}$ Use rule (i) above to obtain: $=\dfrac{1}{x^{18}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.