Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 94

Answer

$49x^6y^2$

Work Step by Step

RECALL: (i) $(a^m)^n=a^{mn}$ (ii) $(ab)^m = a^mb^n$ Use rule (ii) above to obtain: $=7^2(x^3)^2y^2 \\=49(x^3)^2y^2$ Use rule (i) above to obtain: $=49x^{3(2)}y^2 \\=49x^6y^2$
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