Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 91

Answer

$\dfrac{x^2}{y^5}$

Work Step by Step

RECALL: $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$ Use the rule above to obtain: $=x^2 \cdot \dfrac{1}{y^5} \\=\dfrac{x^2}{y^5}$
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