Answer
$r \approx3.389$
Work Step by Step
$\ln (r + 4) = 2$
$\log_e (r + 4) = 2$
$e^{2} = r + 4$
$r = e^{2} - 4$
$r \approx3.389$
Check:
$\ln(( e^{2} - 4) + 4) \overset{?}{=} 2$
$\ln(e^{2} - 4 + 4) \overset{?}{=} 2$
$\ln(e^{2} ) \overset{?}{=} 2$
$2\log_e (e ) \overset{?}{=} 2$
$2(1) \overset{?}{=} 2$
$2= 2$