Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises - Page 535: 34

Answer

$x \approx 33.333$

Work Step by Step

$\log (3x) - 30 = -28$ $\log 3x = -28 + 30$ $\log 3x = 2$ $10^{2} = 3x$ $100 = 3x$ $x = \frac{100}{3}$ $x \approx 33.333$ Check: $\log (3(\frac{100}{3})) - 30 \overset{?}{=} -28$ $\log (100) - 30 \overset{?}{=} -28$ $\log_{10} (10^{2}) - 30 \overset{?}{=} -28$ $2\log_{10} (10) - 30 \overset{?}{=} -28$ $2(1) - 30 \overset{?}{=} -28$ $2 - 30 \overset{?}{=} -28$ $-28= -28$
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