Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises - Page 535: 47

Answer

The correct answer is $x = e^{2} - 2$.

Work Step by Step

$\ln (x+2) = 2$ $\ln_e (x+2) = 2$ $e^{2} = x + 2$ $e^{2} - 2 = x$ $x = e^{2} - 2$ The student thought that the base of the natural log function is $10$, when it actually is $e$. Therefore he/she was unable to find the correct answer.
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