Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises - Page 535: 57

$x=1$

$3\log_2 2x+\log_2 16=7$ $3\log_2 2x+\log_2 2^4=7$ $3\log_2 2x+4=7$ $3\log_2 2x=7-4$ $3\log_2 2x=3$ $\log_2 2x=\frac{3}{3}$ $\log_2 2x=1$ In exponential form $2^1=2x$ $2x=2$ $x=1$ Note; Check the solution in the given equation.