Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review: 6

Answer

$x = \frac{e^{3}+9}{4}$

Work Step by Step

$\ln (4x - 9 )= 3$ $4x - 9 = e^{3}$ $4x = e^{3} + 9$ $x = \frac{e^{3}+9}{4}$ Check: $\ln (4(\frac{e^{3}+9}{4}) - 9 )\overset{?}{=} 3$ $\ln (e^{3}+9 - 9 )\overset{?}{=} 3$ $\ln_{e} (e^{3})\overset{?}{=} 3$ $3= 3$
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