Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 678: 3

Answer

$n = ±8$

Work Step by Step

$n^{2} - 56 = 8$ $n^{2} - 56 - 8 = 0$ $n^{2} - 64 = 0$ $n^{2} = 64$ $n = ±\sqrt {64}$ $n = ±8$ Check: $(-8)^{2} - 56 \overset{?}{=} 8$ $64 - 56 \overset{?}{=} 8$ $8 = 8$ $(8)^{2} - 56 \overset{?}{=} 8$ $64 - 56 \overset{?}{=} 8$ $8 = 8$
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