Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review: 1

Answer

$x = 4$

Work Step by Step

$5(2)^{x} - 4 = 76$ $5(2)^{x} = 80$ $(2)^{x} = 16$ $\log (2)^{x} = \log 16$ $x \log 2 = \log 16$ $x = \frac{\log 16}{\log 2}$ $x = \frac{\log_{10} 2^{4}}{\log_{10} 2^{1}}$ $x = \frac{4}{1}$ $x = 4$ Check: $5(2)^{4} - 4 \overset{?}{=} 76$ $5(16)- 4 \overset{?}{=} 76$ $80 - 4 \overset{?}{=} 76$ $76 = 76$
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