Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 678: 4

Answer

$a = \frac{62}{3}$

Work Step by Step

$\frac{4}{a-6} = \frac{7}{a+5}$ $4(a+5) = 7(a-6)$ $4a + 20 = 7a - 42$ $4a - 7a = -20 - 42$ $-3a = -62$ $a = \frac{62}{3}$ Check: $\frac{4}{(\frac{62}{3})-6} \overset{?}{=} \frac{7}{(\frac{62}{3})+5}$ $\frac{4}{\frac{44}{3}} \overset{?}{=} \frac{7}{\frac{77}{3}}$ $\frac{3}{11} \overset{?}{=} \frac{3}{11}$
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