Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix A - Basic Algebra Review - A Exercises - Page A-15: 62

Answer

$\frac{7}{75} $.

Work Step by Step

The given expression is $=\frac{8}{9} \left (\frac{2}{5}-\frac{7}{10} \right )+\left ( \frac{3}{5} \right )^2$ Get a common denominator inside parentheses first. $=\frac{8}{9} \left (\frac{4}{10}-\frac{7}{10} \right )+\left ( \frac{3}{5} \right )^2$ Subtract numerators inside parentheses. $=\frac{8}{9} \left (-\frac{3}{10} \right )+\left ( \frac{3}{5} \right )^2$ Multiply. $=-\frac{4}{15} +\left ( \frac{3}{5} \right )^2$ Calculate the exponent. $=-\frac{4}{15} + \frac{9}{25} $ Get a common denominator. $=-\frac{20}{75} + \frac{27}{75} $ Subtract numerators because denominators are same. $=\frac{7}{75} $.
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